2500x^4-4y^4=

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Solution for 2500x^4-4y^4= equation:


Simplifying
2500x4 + -4y4 = 0

Solving
2500x4 + -4y4 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y4' to each side of the equation.
2500x4 + -4y4 + 4y4 = 0 + 4y4

Combine like terms: -4y4 + 4y4 = 0
2500x4 + 0 = 0 + 4y4
2500x4 = 0 + 4y4
Remove the zero:
2500x4 = 4y4

Divide each side by '2500'.
x4 = 0.0016y4

Simplifying
x4 = 0.0016y4

Combine like terms: 0.0016y4 + -0.0016y4 = 0.0000
x4 + -0.0016y4 = 0.0000

Factor a difference between two squares.
(x2 + 0.04y2)(x2 + -0.04y2) = 0.0000

Factor a difference between two squares.
(x2 + 0.04y2)((x + 0.2y)(x + -0.2y)) = 0.0000

Subproblem 1

Set the factor '(x2 + 0.04y2)' equal to zero and attempt to solve: Simplifying x2 + 0.04y2 = 0 Solving x2 + 0.04y2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-0.04y2' to each side of the equation. x2 + 0.04y2 + -0.04y2 = 0 + -0.04y2 Combine like terms: 0.04y2 + -0.04y2 = 0.00 x2 + 0.00 = 0 + -0.04y2 x2 = 0 + -0.04y2 Remove the zero: x2 = -0.04y2 Simplifying x2 = -0.04y2 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(x + 0.2y)' equal to zero and attempt to solve: Simplifying x + 0.2y = 0 Solving x + 0.2y = 0 Move all terms containing x to the left, all other terms to the right. Add '-0.2y' to each side of the equation. x + 0.2y + -0.2y = 0 + -0.2y Combine like terms: 0.2y + -0.2y = 0.0 x + 0.0 = 0 + -0.2y x = 0 + -0.2y Remove the zero: x = -0.2y Simplifying x = -0.2y

Subproblem 3

Set the factor '(x + -0.2y)' equal to zero and attempt to solve: Simplifying x + -0.2y = 0 Solving x + -0.2y = 0 Move all terms containing x to the left, all other terms to the right. Add '0.2y' to each side of the equation. x + -0.2y + 0.2y = 0 + 0.2y Combine like terms: -0.2y + 0.2y = 0.0 x + 0.0 = 0 + 0.2y x = 0 + 0.2y Remove the zero: x = 0.2y Simplifying x = 0.2y

Solution

x = {-0.2y, 0.2y}

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